A bag contains 5 red balls, 8 white balls, 4 green balls and 7 black balls. If one ball is drawn at random, find the probability that it is

Posted: 23-07-2022

(i) Black

(ii) Red

(iii) Not green

Answer:- Total number of balls in the bag = 5 + 8 + 4 + 7 = 24

∴ Total number of elementary events = 24

(i) There are 7 black balls in the bag.

∴ Favorable number of elementary events = 7

Henceforth, P (Getting a black ball) = 724 .

(ii) There are 5 red balls in the bag.

∴ Favorable number of elementary events = 5

Henceforth, P (Getting a red ball) =524 .

(iii) There are 5 + 8 + 7 = 20 balls which are not green.

∴ Favorable number of elementary events = 20 Hence, P (No getting a green ball) = 2024=56