Calculate the heat of combustion (kJ) of propane, C3H8 using the listed standard enthalpy of reaction data:

1. C₃​H₈​(g)+5O_2​(g)⟶3CO₂​(g)+4H2​O(g)

2. 3C(s)+4H₂​(g)⟶C₃​H₈​(g)ΔH/kJ=−103.8

3. C(s)+O₂​(g)⟶CO₂​(g)ΔH/kJ=−393.5

4. H₂​(g)+1/2O₂​(g)⟶H₂​O(g)ΔH/kJ=−241.8

A. -2043.9

B. -1532.9

C. -1021.9

D. -739.1

Answer:- A. -2043.9

C₂H_2(g) + 2½O_2(g) → 2CO_2(g) + H₂O_(l) ΔH_c =?

The heat of combustion of propane, C₃H₈, as labeled in the equation C₃H_8(g) + 5O_2(g) → 3CO_2(g) + 4H₂O_(l),

Is –2220 kJ mol^-1 and the heats of creation of carbon dioxide gas also water liquid are –393.5 kJ mol^-1 and -285.8 kJ mol^-1 respectively.