For a 0.040 M ammonia solution : Calculate the PH and POH

Answer:- The pH of solution is 1.398

Solution and Explanation:

converting 0.040 into exponential form,

= 4 x 10⁻²

pH = [H+]

pH = -log [ 4 x 10⁻²]

= – [log 4 + log 10⁻²]

= – [0.602 + (-2)]

= – [ 0.602 – 2]

= – [-1.398]

=     1.398