If the partial pressure of a diatomic gas is 0.630 atm, what is the total pressure of the gas in the container?

Answer: It can be calculated this way:

P1 = 0.63 atm = 2*3 atoms

P2 = 5 moles of diatomic orange

P3 = 6 moles of diatomic blue

P (total) = P1 + P2 + P3

P (total) = 0.63 + 0.63*5/6 + 0.63

P (total) = 1.79 atm