Answer:- Correct option is B)
I=10A, θ=45o, B=0.2T
∴F=IlBsinθ
∴lF=IBsin45o=10×0.2×2
1=2
2Nm−1
The magnetic force per unit length on a wire carrying a current of 10 A and making an angle of 45 degree with the direction of a uniform magnetic field of 0.20 T is
Posted: 19-08-2022