{"id":37474,"date":"2024-06-26T08:19:38","date_gmt":"2024-06-26T08:19:38","guid":{"rendered":"https:\/\/www.greatassignmenthelp.com\/questions\/?p=37474"},"modified":"2024-06-26T08:19:38","modified_gmt":"2024-06-26T08:19:38","slug":"solve-the-following-quadratic-equation-by-factoring-x211x280","status":"publish","type":"post","link":"https:\/\/www.greatassignmenthelp.com\/questions\/solve-the-following-quadratic-equation-by-factoring-x211x280\/","title":{"rendered":"Solve the following quadratic equation by factoring.  x2+11x+28=0"},"content":{"rendered":"<p data-pm-slice=\"1 1 []\"><strong>Question:-<\/strong> Solve the following quadratic equation by factoring. x2+11x+28=0<\/p>\n<p><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\"><strong>Answer:<\/strong> To solve this quadratic equation by factoring, we&#8217;ll follow these steps<\/span><\/span><\/p>\n<p><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">First, let&#8217;s identify the coefficients: a = 1, b = 11, c = 28<\/span><\/span><\/p>\n<p><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">Thus we have two numbers which, when they are multiplied, will produce ac and that is 1*28 =28 and adding two numbers will produce b as 11. These numbers are 7 and 4<\/span><\/span><\/p>\n<p><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">We can rewrite the middle term using these numbers: x^2+7x+4x+28=0<\/span><\/span><\/p>\n<p><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">Now we can factor by grouping: Again, it gets to simplify the equation to get ( 2x + 7) + (4x + 28) = 0 <\/span><\/span><\/p>\n<p><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">thus minimizing the expression gets x(x + 7) + 4(x + 7) = 0 <\/span><\/span><\/p>\n<p><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">In order to factor it the expression gets into (x + 7)(x + 4) = 0<\/span><\/span><\/p>\n<p><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">Using the zero-product property, we can set each factor to zero<\/span><\/span><\/p>\n<p><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">So, we get x = -7 or x = -4 (after substituting x + 7 = 0 or x + 4 = 0. )<\/span><\/span><\/p>\n<p><span style=\"font-family: Times New Roman, serif;\"><span style=\"font-size: medium;\">As such, they are the solutions to the equation x\u00b2 + 11x + 28 = 0; this means that the solutions are -7 and -4.<\/span><\/span><a name=\"_GoBack\"><\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Question:- Solve the following quadratic equation by factoring. x2+11x+28=0 Answer: To solve this quadratic equation by factoring, we&#8217;ll follow these steps First, let&#8217;s identify the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v23.5 - 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