{"id":8473,"date":"2022-11-18T09:00:08","date_gmt":"2022-11-18T09:00:08","guid":{"rendered":"https:\/\/www.greatassignmenthelp.com\/questions\/?p=8473"},"modified":"2023-12-21T06:46:34","modified_gmt":"2023-12-21T06:46:34","slug":"a-stock-solution-containing-mn2-ions-was-prepared-by-dissolving","status":"publish","type":"post","link":"https:\/\/www.greatassignmenthelp.com\/questions\/a-stock-solution-containing-mn2-ions-was-prepared-by-dissolving\/","title":{"rendered":"A stock solution containing Mn2 ions was prepared by dissolving 1.584 g pure manganese metal in nitric acid and diluting to a final volume of 1.000 L."},"content":{"rendered":"

The following solutions were then prepared by dilution:<\/p>\n

1. For solution A, 50.00 mL of stock solution was diluted to 1000.0 mL.<\/p>\n

2. For solution B, 10.00 mL of solution A was diluted to 250.0 mL.<\/p>\n

3. For solution C, 10.00 mL of solution B was diluted to 500.0 mL.<\/p>\n

Calculate the concentrations of the stock solution and solutions A, B, and C.<\/p>\n

Answer:-\u00a0<\/strong>1.534g\u00a0 Mn + HNO3 \u2192\u2192 Khal Volume = 1,0006 1504g (lam Mn\/3 1,504 Mn 54.949 Mr.) =0.02883 mel mu<\/p>\n

M\u2081 = md = 0.02863md Muta L 1,000 2 = 0,02883M Mn+ 2 = M,<\/p>\n

M\u2082 = M.V\u2081\/v2 = (0.02883 m) (32,00ml) = – (1000,0 ml) 0.001.4421 minta (A 1,442×10-3<\/p>\n

M\u2082 = 10,0014412M) (10.09) (250.0 ml)=\u00a0 0.0000576BM Mnta (B 5.766×10-5 My<\/p>\n

= (0100005760M) (10.00me) (500.0me) = 0.000001154 MY Muta (@ 1.154×10-4<\/p>\n","protected":false},"excerpt":{"rendered":"

The following solutions were then prepared by dilution: 1. For solution A, 50.00 mL of stock solution was diluted to 1000.0 mL. 2. For solution […]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[27],"tags":[],"yoast_head":"\nA stock solution containing Mn2 ions was prepared by dissolving 1.584 g pure manganese metal in nitric acid and diluting to a final volume of 1.000 L.<\/title>\n<meta name=\"description\" content=\"A stock solution containing Mn2 ions was prepared by dissolving 1.584 g pure manganese metal in nitric acid and diluting to a final volume of 1.000 L. The following solutions were then prepared by dilution: For solution A, 50.00 mL of stock solution was diluted to 1000.0 mL. For solution B, 10.00 mL of solution A was diluted to 250.0 mL. For solution C, 10.00 mL of solution B was diluted to 500.0 mL. 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